180=w^2+6w

Solution for 180=w^2+6w equation:

180=w^2+6w

We move all terms to the left:

180-(w^2+6w)=0

We get rid of parentheses

-w^2-6w+180=0

We add all the numbers together, and all the variables

-1w^2-6w+180=0

a = -1; b = -6; c = +180;
Δ = b2-4ac
Δ = -62-4·(-1)·180
Δ = 756
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{756}=\sqrt{36*21}=\sqrt{36}*\sqrt{21}=6\sqrt{21}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6\sqrt{21}}{2*-1}=\frac{6-6\sqrt{21}}{-2}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6\sqrt{21}}{2*-1}=\frac{6+6\sqrt{21}}{-2}
$